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HOME TUITION CAPSULE ON QUANTITATIVE APTITUDE PERCENTAGES MATERIAL

PERCENTAGES :To convert percentage into fractions divide the given value with hundred
To convert fraction into percentage multiple the given fraction with 100% 50% = 50/100 = 1/2
1/2 = 1/2(100%) = 50%
EX:
convert the folowing percentages into fraction
1) 60% = 60/100 = 3/5
2) 12.5 % = 12.5/100 = 5/40 = 1/8
3) 33 (1/3)% = 100/3 = 1/3
4) 16(2/3)% = 50/(3*100) = 1/6
EX:
convert the following fractions into percentage



1) (3/4)*100 = 75 %
2) (4/5) * 100 = 80%
3) (2/3) * 100 = 200/3 = 66(2/3)%
4) (1/5) *100 = 20%
5) (1/12)*100 = 25/3 % = 8 (1/3)%
NOTE:
50% = 1/2
25% = 1/4
12(1/2)% = 1/8
6(1/4)% = 1/16
66 (2/3)% = 2/3
33(1/3)% = 1/3
16(2/3) % = 1/6
8(1/3)% = 1/12
75% = 3/4
14 (2/7)% = 1/7
11(1/9)% = 1/9
9 (1/11)% = 1/11
NOTE:
1/1 = 100%
1/2 = 50%
1/3 = 75%
1/4 = 25%
1/5 = 20%
1/6 = 16 (2/3)%
1/7 = 14(2/7)%
1/8 = 12(1/2)%
1/4 = 11(1/4)%
1/10 = 10%
1/11 = 9(1/11)%
1/12 = 8(1/3)%
FORMULAE:
1 x%y = (x/100)y
(xy)/100
2 x is what percentage of y
what = (100%x)/y
is/of just remember
EG:
IN 250 FIND…

HOME TUITION- QUANTITATIVE APTITUDE SIMPLE INTEREST MATERIAL

HOME TUITION QUANTITATIVE APTITUDE SIMPLE INTEREST  MATERIAL :
material on simple interest

simple interest :

SI = PTR/100

P = PRINCIPLE AMOUNT

T = TIME PERIOD

R = RATE OF INTEREST

FIND SIMPLE INTEREST ON 6000 RS FOR 5 YEARS AT 8 % ANUM?
I = PTR/100
(6000*5*8)/100

2400

IN WHAT TIME THE SIMPLE INTEREST ON 4000 RS AT 6% PER ANUM BE 960 RS?
T = 100ST/(PR)

(460*100)/(4000*6)

AT WHAT RATE PERCENTAGE PER ANUM DO THE SIMPLE INTEREST 1800?
P = 18000

T = 5

SI = 2700
R = 100SI/(PT)

= 18000

FIND THE SIMPLE INTEREST ON 24000 PER 8 YEARS 4 MONTHS AT 3 PERCENTAGE PER ANUM?

4 MONTHS = IN A YEAR 12 MONTHS

SO 4/12

1/3

I = (24000*3*8(4/12))/100
FIND SIMPLE INTEREST ON 8000 RS PER 3 YEARS 3 MONTHS AT 4(1/2)% PER ANUM?
8000* 3(1/4)*(9/2)
……………….

100

quantitative aptitude material on allegation problems-home tuitions

Bankers adda quantitative aptitude material on allegation problemsAllegation problems
EG:

 IN A CLASS AVERAGE AGE OF 60 STUDENTS IS 15 YEARS AVERAGE AGE OF BOYS IS 13 YEARS AND GIRLS IS 16

YEARS FIND NO OF BOYS AND NO OF GIRLS?


                    BOYS            GIRLS

                   13               16


                           15

                    16-15= 1    15-13 = 2



                  3 PARTS   60


                 1 PART   ?


                      60/3  = 20



                    2*20 = 40


                20,40

EG:

 IN A SOLUTION THERE IS 20% FINISHED

IN ANOTHER THERE IS 30% FINISHED

HOW MANY LITERS OF FIRST SOLUTION IS MIXED WITH 60 LITERS OF SECOND SOLUTION SO THAT THERE IS

24% IN THE MIXURE?



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